**Direction (1-9): In each of the following question, a series is given with one or two term missing. Find out the missing term from the given alternatives.**

**Q1. 0, F, 6, L, 24, R, ? , ?**

(a) 60, Y

(b) 60, X

(c) 120, X

(d) 120, Y

**Ans.(b)**

**Sol. Clearly, there are 2 series:**

**I: 1^3-1,2^3-2,3^3-3,4^3-4**

**II. F, L, R, X**

**In 2nd series, there is a gap of 6.**

**∴ Missing term = [4^3-4, X] = [60,X]**

**Q2. 4, D, 6, F, 12, L, 14, N, 28, ?**

(a) A

(b) B

(c) C

(d) D

**Ans.(b)**

**Sol. The given sequence is a combination of two series:**

**I. 4, 6, 12, 14, 28**

**II. D, F, L, N …**

**Now, the pattern followed in 1st series is: +2, ×2, +2, ×2**

**In 2nd series Letter is based on the number which appears before it.**

**So, missing letter = 28 i.e. B**

**Q3. 1, C, 3, F, 7, I, 13, ? , 21**

(a) J

(b) K

(c) L

(d) M

**Ans.(c)**

**Sol. Clearly, the given sequence is a combination of two series:**

**I. 1, 3, 7, 13, 21**

**II. C, F, I, ?**

**The pattern followed in I is +2, +4, … and**

**the pattern followed in II is +3.**

**So, missing number = I + 3 = 12 i.e. L**

**Q4. GH, JL, NQ, SW, YD, ?**

(a) EG

(b) FJ

(c) HL

(d) FL

Ans ;

**Q5. ajs, gpy, ?, sbk, yhq**

(a) dmv

(b) mve

(c) oua

(d) qrv

Ans :

**Q6. AI, BJ, CK, ?**

(a) DL

(b) DM

(c) JH

(d) LN

Ans :

**Q7. Z, 24, T, 18, Q, 15, J, 8, W, ?**

(a) 20

(b) 21

(c) 6

(d) 5

**Ans.(b)**

**Sol. Clearly, the given series is a combination of : [Letter, (Letter value – 2)]**

**∴ Missing term = W- 2 = 23 – 2 = 21**

**Q8. A, 1, D, 4, I, 9, P, 16, ?, ?**

(a) X, 25

(b) Y, 25

(c) Z, 25

(d) A, 25

**Ans.(b)**

**Sol. The given sequence is a combination of two series:**

**A, D, I, P, ?****1, 4, 9, 16, ?**

**Now, the pattern followed in each of the above two series is: 1 ^{2}, 2^{2}, 3^{2}, 4^{2}, 5^{2}**

**But 1 ^{st} series contains Alphabets.**

**So, missing terms= (5 ^{2} , ^{ }5^{2}) = Y, 25.**

**Q9. AD, 3, GN, 7, QV, 5, FJ, ?**

(a) 12

(b) 4

(c) 11

(d) 13

**Ans.(b)**

**Sol. Clearly, the given sequence is a combination of (Pair of Alphabets, Difference between Alphabets)**

**So, missing term = Difference between F & J = 10 – 6 = 4**

**Directions (10-15): In the following question, one term in the number series is wrong. Find out the wrong term.**

**Q10. 1, 3, 10, 21, 64, 129, 356, 777**

(a) 129

(b) 21

(c) 356

(d) 64

**Ans.(c)**

**Sol. The correct pattern ×2+1, ×3+1, ×2 + 1, ×3 + 1, ……**

**So, 356 is wrong and must be replaced by (129 × 3 + 1) i.e. 388.**

**Q11. 0, 2, 10, 42, 171, 682**

(a) 10

(b) 42

(c) 171

(d) 682

**Ans.(c)**

**Sol. The numbers are forwarded by (×2^2+2)**

**So. 171 is wrong. The correct term should be 170**

**[42×2**

^{2}+ 2]

**Q12. abd, dgk, hms, mtb, sbk**

(a) hms

(b) mtb

(c) sbk

(d) abd

solution :

**Q13. 684, 618, 564, 519, 486, 464, 453**

(a) 618

(b) 564

(c) 486

(d) 519

**Ans.(b)**

**Sol. The correct pattern is –66, –55, –44, –33, –22, –11.**

**So, 564 is wrong and must be replaced by (618–55) i.e. 563**

**Q14. 25, 36, 49, 81, 121, 169, 225**

(a) 36

(b) 49

(c) 169

(d) 225

**Ans.(a)**

**Sol. The correct sequence is 5^2,7^2,9^2, 11^2,13^2,15^2. So, 36 is wrong.**

**Q15. AA, BD, CI, DP, EZ**

(a) BD

(b) CI

(c) DP

(d) EZ

Ans.(d)

Sol. Series contains pair of alphabets, numerical value of 2nd alphabet is the square of numerical value of 1st alphabet.

So, EZ is wrong because E= 5

& 52 =25 i.e. Y

Sol. Series contains pair of alphabets, numerical value of 2nd alphabet is the square of numerical value of 1st alphabet.

So, EZ is wrong because E= 5

& 52 =25 i.e. Y